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7x-1(4x+5)-2=2(8x+20)-7x+5
We move all terms to the left:
7x-1(4x+5)-2-(2(8x+20)-7x+5)=0
We calculate terms in parentheses: -(2(8x+20)-7x+5), so:We get rid of parentheses
2(8x+20)-7x+5
We add all the numbers together, and all the variables
-7x+2(8x+20)+5
We multiply parentheses
-7x+16x+40+5
We add all the numbers together, and all the variables
9x+45
Back to the equation:
-(9x+45)
7x-1(4x+5)-9x-45-2=0
We add all the numbers together, and all the variables
-2x-1(4x+5)-47=0
We move all terms containing x to the left, all other terms to the right
-2x-1(4x+5)=47
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