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x-3 = 5;x
x
(2*x+1)^2+x^3 < (x+1)^3+12;x
x
x^2-(12*x)-28 < 0;x
x
-(x-3)^2-2*x^2 >= 0;x
x
| b+12=16 | | y+7=18 | | 0=-16t^2+32t+200 | | -259=5-6(6x+8) | | (x-4)2=49 | | -(6a+1)+2(3-q)=q | | 14x+7y+9x=-1z+1y-12z | | 5(k-8)=7(3k+1)+17 | | 1w=135+6j | | 3(1-4x)-2=-95 | | 4X-4=7X-25 | | 90/x=14/84 | | -2(8x+8)=96 | | 3u-17=25 | | 3x-9=8x+6 | | 3s^2+10s+3=0 | | -3x+2=22 | | 2x+1=x*x | | x*x-2=2x+1 | | 5X-23=2 | | -2y=x+11 | | 5x+317.5=2080 | | -8y=4.48 | | 2ycubed+7ysquared+6y=0 | | 5y+16=3y+6y | | 7x+4x+3=90 | | Y=.25x^2-1.5x+3 | | z^2+4iz=0 | | z^2+4is=0 | | 191-u=54 | | x^2+5x-18.75=0 | | 8(x-4.6)=1.6 |