7x-10(x-1)=3(x-2)-5(x+3)

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Solution for 7x-10(x-1)=3(x-2)-5(x+3) equation: 



7x-10(x-1)=3(x-2)-5(x+3)

We move all terms to the left:

7x-10(x-1)-(3(x-2)-5(x+3))=0

We multiply parentheses

7x-10x-(3(x-2)-5(x+3))+10=0



We calculate terms in parentheses: -(3(x-2)-5(x+3)), so:

3(x-2)-5(x+3)

We multiply parentheses

3x-5x-6-15

We add all the numbers together, and all the variables

-2x-21

Back to the equation:

-(-2x-21)



We add all the numbers together, and all the variables

-3x-(-2x-21)+10=0

We get rid of parentheses

-3x+2x+21+10=0

We add all the numbers together, and all the variables

-1x+31=0

We move all terms containing x to the left, all other terms to the right

-x=-31

x=-31/-1

x=+31

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