7x-10-2x=2(x+3)+15

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Solution for 7x-10-2x=2(x+3)+15 equation: 



7x-10-2x=2(x+3)+15

We move all terms to the left:

7x-10-2x-(2(x+3)+15)=0

We add all the numbers together, and all the variables

5x-(2(x+3)+15)-10=0



We calculate terms in parentheses: -(2(x+3)+15), so:

2(x+3)+15

We multiply parentheses

2x+6+15

We add all the numbers together, and all the variables

2x+21

Back to the equation:

-(2x+21)



We get rid of parentheses

5x-2x-21-10=0

We add all the numbers together, and all the variables

3x-31=0

We move all terms containing x to the left, all other terms to the right

3x=31

x=31/3

x=10+1/3

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