7x-10=3(x-2)+4(x-2)

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Solution for 7x-10=3(x-2)+4(x-2) equation:


Simplifying
7x + -10 = 3(x + -2) + 4(x + -2)

Reorder the terms:
-10 + 7x = 3(x + -2) + 4(x + -2)

Reorder the terms:
-10 + 7x = 3(-2 + x) + 4(x + -2)
-10 + 7x = (-2 * 3 + x * 3) + 4(x + -2)
-10 + 7x = (-6 + 3x) + 4(x + -2)

Reorder the terms:
-10 + 7x = -6 + 3x + 4(-2 + x)
-10 + 7x = -6 + 3x + (-2 * 4 + x * 4)
-10 + 7x = -6 + 3x + (-8 + 4x)

Reorder the terms:
-10 + 7x = -6 + -8 + 3x + 4x

Combine like terms: -6 + -8 = -14
-10 + 7x = -14 + 3x + 4x

Combine like terms: 3x + 4x = 7x
-10 + 7x = -14 + 7x

Add '-7x' to each side of the equation.
-10 + 7x + -7x = -14 + 7x + -7x

Combine like terms: 7x + -7x = 0
-10 + 0 = -14 + 7x + -7x
-10 = -14 + 7x + -7x

Combine like terms: 7x + -7x = 0
-10 = -14 + 0
-10 = -14

Solving
-10 = -14

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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