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7x-11=5(x-2)+2x+-1
We move all terms to the left:
7x-11-(5(x-2)+2x+-1)=0
We use the square of the difference formula
7x-(5(x-2)+2x-1)-11=0
We calculate terms in parentheses: -(5(x-2)+2x-1), so:We get rid of parentheses
5(x-2)+2x-1
We add all the numbers together, and all the variables
2x+5(x-2)-1
We multiply parentheses
2x+5x-10-1
We add all the numbers together, and all the variables
7x-11
Back to the equation:
-(7x-11)
7x-7x+11-11=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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