7x-13-4x=3(x-4)-1

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Solution for 7x-13-4x=3(x-4)-1 equation: 



7x-13-4x=3(x-4)-1

We move all terms to the left:

7x-13-4x-(3(x-4)-1)=0

We add all the numbers together, and all the variables

3x-(3(x-4)-1)-13=0



We calculate terms in parentheses: -(3(x-4)-1), so:

3(x-4)-1

We multiply parentheses

3x-12-1

We add all the numbers together, and all the variables

3x-13

Back to the equation:

-(3x-13)



We get rid of parentheses

3x-3x+13-13=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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