7x-2(-2x+1)=8-3(x-2)

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Solution for 7x-2(-2x+1)=8-3(x-2) equation: 



7x-2(-2x+1)=8-3(x-2)

We move all terms to the left:

7x-2(-2x+1)-(8-3(x-2))=0

We multiply parentheses

7x+4x-(8-3(x-2))-2=0



We calculate terms in parentheses: -(8-3(x-2)), so:

8-3(x-2)

determiningTheFunctionDomain
-3(x-2)+8

We multiply parentheses

-3x+6+8

We add all the numbers together, and all the variables

-3x+14

Back to the equation:

-(-3x+14)



We add all the numbers together, and all the variables

11x-(-3x+14)-2=0

We get rid of parentheses

11x+3x-14-2=0

We add all the numbers together, and all the variables

14x-16=0

We move all terms containing x to the left, all other terms to the right

14x=16

x=16/14

x=1+1/7

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