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7x-2(3x+)=4x-(3-x)-19
We move all terms to the left:
7x-2(3x+)-(4x-(3-x)-19)=0
We add all the numbers together, and all the variables
7x-2(+3x)-(4x-(-1x+3)-19)=0
We multiply parentheses
7x-6x-(4x-(-1x+3)-19)=0
We calculate terms in parentheses: -(4x-(-1x+3)-19), so:We add all the numbers together, and all the variables
4x-(-1x+3)-19
We get rid of parentheses
4x+1x-3-19
We add all the numbers together, and all the variables
5x-22
Back to the equation:
-(5x-22)
x-(5x-22)=0
We get rid of parentheses
x-5x+22=0
We add all the numbers together, and all the variables
-4x+22=0
We move all terms containing x to the left, all other terms to the right
-4x=-22
x=-22/-4
x=5+1/2
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