7x-2(3x+1)=4x(3-x)-19

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Solution for 7x-2(3x+1)=4x(3-x)-19 equation: 



7x-2(3x+1)=4x(3-x)-19

We move all terms to the left:

7x-2(3x+1)-(4x(3-x)-19)=0

We add all the numbers together, and all the variables

7x-2(3x+1)-(4x(-1x+3)-19)=0

We multiply parentheses

7x-6x-(4x(-1x+3)-19)-2=0



We calculate terms in parentheses: -(4x(-1x+3)-19), so:

4x(-1x+3)-19

We multiply parentheses

-4x^2+12x-19

Back to the equation:

-(-4x^2+12x-19)



We add all the numbers together, and all the variables

-(-4x^2+12x-19)+x-2=0

We get rid of parentheses

4x^2-12x+x+19-2=0

We add all the numbers together, and all the variables

4x^2-11x+17=0

a = 4; b = -11; c = +17;
Δ = b2-4ac
Δ = -112-4·4·17
Δ = -151
Delta is less than zero, so there is no solution for the equation

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