7x-2(3x+8)=5(x-1)+1

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Solution for 7x-2(3x+8)=5(x-1)+1 equation: 



7x-2(3x+8)=5(x-1)+1

We move all terms to the left:

7x-2(3x+8)-(5(x-1)+1)=0

We multiply parentheses

7x-6x-(5(x-1)+1)-16=0



We calculate terms in parentheses: -(5(x-1)+1), so:

5(x-1)+1

We multiply parentheses

5x-5+1

We add all the numbers together, and all the variables

5x-4

Back to the equation:

-(5x-4)



We add all the numbers together, and all the variables

x-(5x-4)-16=0

We get rid of parentheses

x-5x+4-16=0

We add all the numbers together, and all the variables

-4x-12=0

We move all terms containing x to the left, all other terms to the right

-4x=12

x=12/-4

x=-3

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