7x-2(4-3x)=3(x-4)-16

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Solution for 7x-2(4-3x)=3(x-4)-16 equation: 



7x-2(4-3x)=3(x-4)-16

We move all terms to the left:

7x-2(4-3x)-(3(x-4)-16)=0

We add all the numbers together, and all the variables

7x-2(-3x+4)-(3(x-4)-16)=0

We multiply parentheses

7x+6x-(3(x-4)-16)-8=0



We calculate terms in parentheses: -(3(x-4)-16), so:

3(x-4)-16

We multiply parentheses

3x-12-16

We add all the numbers together, and all the variables

3x-28

Back to the equation:

-(3x-28)



We add all the numbers together, and all the variables

13x-(3x-28)-8=0

We get rid of parentheses

13x-3x+28-8=0

We add all the numbers together, and all the variables

10x+20=0

We move all terms containing x to the left, all other terms to the right

10x=-20

x=-20/10

x=-2

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