7x-2(4-3x)=5(x-3)-41

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Solution for 7x-2(4-3x)=5(x-3)-41 equation: 



7x-2(4-3x)=5(x-3)-41

We move all terms to the left:

7x-2(4-3x)-(5(x-3)-41)=0

We add all the numbers together, and all the variables

7x-2(-3x+4)-(5(x-3)-41)=0

We multiply parentheses

7x+6x-(5(x-3)-41)-8=0



We calculate terms in parentheses: -(5(x-3)-41), so:

5(x-3)-41

We multiply parentheses

5x-15-41

We add all the numbers together, and all the variables

5x-56

Back to the equation:

-(5x-56)



We add all the numbers together, and all the variables

13x-(5x-56)-8=0

We get rid of parentheses

13x-5x+56-8=0

We add all the numbers together, and all the variables

8x+48=0

We move all terms containing x to the left, all other terms to the right

8x=-48

x=-48/8

x=-6

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