7x-2(4-3x)=5(x-5)-7

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Solution for 7x-2(4-3x)=5(x-5)-7 equation: 



7x-2(4-3x)=5(x-5)-7

We move all terms to the left:

7x-2(4-3x)-(5(x-5)-7)=0

We add all the numbers together, and all the variables

7x-2(-3x+4)-(5(x-5)-7)=0

We multiply parentheses

7x+6x-(5(x-5)-7)-8=0



We calculate terms in parentheses: -(5(x-5)-7), so:

5(x-5)-7

We multiply parentheses

5x-25-7

We add all the numbers together, and all the variables

5x-32

Back to the equation:

-(5x-32)



We add all the numbers together, and all the variables

13x-(5x-32)-8=0

We get rid of parentheses

13x-5x+32-8=0

We add all the numbers together, and all the variables

8x+24=0

We move all terms containing x to the left, all other terms to the right

8x=-24

x=-24/8

x=-3

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