7x-2(4x-4)=3(x-8)

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Solution for 7x-2(4x-4)=3(x-8) equation: 



7x-2(4x-4)=3(x-8)

We move all terms to the left:

7x-2(4x-4)-(3(x-8))=0

We multiply parentheses

7x-8x-(3(x-8))+8=0



We calculate terms in parentheses: -(3(x-8)), so:

3(x-8)

We multiply parentheses

3x-24

Back to the equation:

-(3x-24)



We add all the numbers together, and all the variables

-1x-(3x-24)+8=0

We get rid of parentheses

-1x-3x+24+8=0

We add all the numbers together, and all the variables

-4x+32=0

We move all terms containing x to the left, all other terms to the right

-4x=-32

x=-32/-4

x=+8

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