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7x-2(4x-6)x=3
We move all terms to the left:
7x-2(4x-6)x-(3)=0
We multiply parentheses
-8x^2+7x+12x-3=0
We add all the numbers together, and all the variables
-8x^2+19x-3=0
a = -8; b = 19; c = -3;
Δ = b2-4ac
Δ = 192-4·(-8)·(-3)
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{265}}{2*-8}=\frac{-19-\sqrt{265}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{265}}{2*-8}=\frac{-19+\sqrt{265}}{-16} $
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