7x-2(5+4x)=20+3(-2-3x)

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Solution for 7x-2(5+4x)=20+3(-2-3x) equation: 



7x-2(5+4x)=20+3(-2-3x)

We move all terms to the left:

7x-2(5+4x)-(20+3(-2-3x))=0

We add all the numbers together, and all the variables

7x-2(4x+5)-(20+3(-3x-2))=0

We multiply parentheses

7x-8x-(20+3(-3x-2))-10=0



We calculate terms in parentheses: -(20+3(-3x-2)), so:

20+3(-3x-2)

determiningTheFunctionDomain
3(-3x-2)+20

We multiply parentheses

-9x-6+20

We add all the numbers together, and all the variables

-9x+14

Back to the equation:

-(-9x+14)



We add all the numbers together, and all the variables

-1x-(-9x+14)-10=0

We get rid of parentheses

-1x+9x-14-10=0

We add all the numbers together, and all the variables

8x-24=0

We move all terms containing x to the left, all other terms to the right

8x=24

x=24/8

x=3

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