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7x-2(x-5)=5(x+1)+4
We move all terms to the left:
7x-2(x-5)-(5(x+1)+4)=0
We multiply parentheses
7x-2x-(5(x+1)+4)+10=0
We calculate terms in parentheses: -(5(x+1)+4), so:We add all the numbers together, and all the variables
5(x+1)+4
We multiply parentheses
5x+5+4
We add all the numbers together, and all the variables
5x+9
Back to the equation:
-(5x+9)
5x-(5x+9)+10=0
We get rid of parentheses
5x-5x-9+10=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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