7x-2(x-8)=5(x+1)+3

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Solution for 7x-2(x-8)=5(x+1)+3 equation: 


Simplifying
7x + -2(x + -8) = 5(x + 1) + 3

Reorder the terms:
7x + -2(-8 + x) = 5(x + 1) + 3
7x + (-8 * -2 + x * -2) = 5(x + 1) + 3
7x + (16 + -2x) = 5(x + 1) + 3

Reorder the terms:
16 + 7x + -2x = 5(x + 1) + 3

Combine like terms: 7x + -2x = 5x
16 + 5x = 5(x + 1) + 3

Reorder the terms:
16 + 5x = 5(1 + x) + 3
16 + 5x = (1 * 5 + x * 5) + 3
16 + 5x = (5 + 5x) + 3

Reorder the terms:
16 + 5x = 5 + 3 + 5x

Combine like terms: 5 + 3 = 8
16 + 5x = 8 + 5x

Add '-5x' to each side of the equation.
16 + 5x + -5x = 8 + 5x + -5x

Combine like terms: 5x + -5x = 0
16 + 0 = 8 + 5x + -5x
16 = 8 + 5x + -5x

Combine like terms: 5x + -5x = 0
16 = 8 + 0
16 = 8

Solving
16 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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