7x-2(x-8)=5(x+1)+5

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Solution for 7x-2(x-8)=5(x+1)+5 equation: 



7x-2(x-8)=5(x+1)+5

We move all terms to the left:

7x-2(x-8)-(5(x+1)+5)=0

We multiply parentheses

7x-2x-(5(x+1)+5)+16=0



We calculate terms in parentheses: -(5(x+1)+5), so:

5(x+1)+5

We multiply parentheses

5x+5+5

We add all the numbers together, and all the variables

5x+10

Back to the equation:

-(5x+10)



We add all the numbers together, and all the variables

5x-(5x+10)+16=0

We get rid of parentheses

5x-5x-10+16=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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