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7x-2(x-9)=2(x-4)+9
We move all terms to the left:
7x-2(x-9)-(2(x-4)+9)=0
We multiply parentheses
7x-2x-(2(x-4)+9)+18=0
We calculate terms in parentheses: -(2(x-4)+9), so:We add all the numbers together, and all the variables
2(x-4)+9
We multiply parentheses
2x-8+9
We add all the numbers together, and all the variables
2x+1
Back to the equation:
-(2x+1)
5x-(2x+1)+18=0
We get rid of parentheses
5x-2x-1+18=0
We add all the numbers together, and all the variables
3x+17=0
We move all terms containing x to the left, all other terms to the right
3x=-17
x=-17/3
x=-5+2/3
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