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7x-2=5/6x-4
We move all terms to the left:
7x-2-(5/6x-4)=0
Domain of the equation: 6x-4)!=0We get rid of parentheses
x∈R
7x-5/6x+4-2=0
We multiply all the terms by the denominator
7x*6x+4*6x-2*6x-5=0
Wy multiply elements
42x^2+24x-12x-5=0
We add all the numbers together, and all the variables
42x^2+12x-5=0
a = 42; b = 12; c = -5;
Δ = b2-4ac
Δ = 122-4·42·(-5)
Δ = 984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{984}=\sqrt{4*246}=\sqrt{4}*\sqrt{246}=2\sqrt{246}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{246}}{2*42}=\frac{-12-2\sqrt{246}}{84} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{246}}{2*42}=\frac{-12+2\sqrt{246}}{84} $
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