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7x-3(2x+5)=6(2+3x)-31
We move all terms to the left:
7x-3(2x+5)-(6(2+3x)-31)=0
We add all the numbers together, and all the variables
7x-3(2x+5)-(6(3x+2)-31)=0
We multiply parentheses
7x-6x-(6(3x+2)-31)-15=0
We calculate terms in parentheses: -(6(3x+2)-31), so:We add all the numbers together, and all the variables
6(3x+2)-31
We multiply parentheses
18x+12-31
We add all the numbers together, and all the variables
18x-19
Back to the equation:
-(18x-19)
x-(18x-19)-15=0
We get rid of parentheses
x-18x+19-15=0
We add all the numbers together, and all the variables
-17x+4=0
We move all terms containing x to the left, all other terms to the right
-17x=-4
x=-4/-17
x=4/17
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