7x-3(2x-5)=(2+3x)-31

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Solution for 7x-3(2x-5)=(2+3x)-31 equation: 



7x-3(2x-5)=(2+3x)-31

We move all terms to the left:

7x-3(2x-5)-((2+3x)-31)=0

We add all the numbers together, and all the variables

7x-3(2x-5)-((3x+2)-31)=0

We multiply parentheses

7x-6x-((3x+2)-31)+15=0



We calculate terms in parentheses: -((3x+2)-31), so:

(3x+2)-31

We get rid of parentheses

3x+2-31

We add all the numbers together, and all the variables

3x-29

Back to the equation:

-(3x-29)



We add all the numbers together, and all the variables

x-(3x-29)+15=0

We get rid of parentheses

x-3x+29+15=0

We add all the numbers together, and all the variables

-2x+44=0

We move all terms containing x to the left, all other terms to the right

-2x=-44

x=-44/-2

x=+22

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