7x-3(x+1)=2(3x+4)+x-6

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Solution for 7x-3(x+1)=2(3x+4)+x-6 equation: 



7x-3(x+1)=2(3x+4)+x-6

We move all terms to the left:

7x-3(x+1)-(2(3x+4)+x-6)=0

We multiply parentheses

7x-3x-(2(3x+4)+x-6)-3=0



We calculate terms in parentheses: -(2(3x+4)+x-6), so:

2(3x+4)+x-6

We add all the numbers together, and all the variables

x+2(3x+4)-6

We multiply parentheses

x+6x+8-6

We add all the numbers together, and all the variables

7x+2

Back to the equation:

-(7x+2)



We add all the numbers together, and all the variables

4x-(7x+2)-3=0

We get rid of parentheses

4x-7x-2-3=0

We add all the numbers together, and all the variables

-3x-5=0

We move all terms containing x to the left, all other terms to the right

-3x=5

x=5/-3

x=-1+2/3

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