7x-3(x-4)=6(2x-10)

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Solution for 7x-3(x-4)=6(2x-10) equation: 



7x-3(x-4)=6(2x-10)

We move all terms to the left:

7x-3(x-4)-(6(2x-10))=0

We multiply parentheses

7x-3x-(6(2x-10))+12=0



We calculate terms in parentheses: -(6(2x-10)), so:

6(2x-10)

We multiply parentheses

12x-60

Back to the equation:

-(12x-60)



We add all the numbers together, and all the variables

4x-(12x-60)+12=0

We get rid of parentheses

4x-12x+60+12=0

We add all the numbers together, and all the variables

-8x+72=0

We move all terms containing x to the left, all other terms to the right

-8x=-72

x=-72/-8

x=+9

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