7x-3(x-6)=2(x-4)+6

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Solution for 7x-3(x-6)=2(x-4)+6 equation: 



7x-3(x-6)=2(x-4)+6

We move all terms to the left:

7x-3(x-6)-(2(x-4)+6)=0

We multiply parentheses

7x-3x-(2(x-4)+6)+18=0



We calculate terms in parentheses: -(2(x-4)+6), so:

2(x-4)+6

We multiply parentheses

2x-8+6

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

4x-(2x-2)+18=0

We get rid of parentheses

4x-2x+2+18=0

We add all the numbers together, and all the variables

2x+20=0

We move all terms containing x to the left, all other terms to the right

2x=-20

x=-20/2

x=-10

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