7x-3(x-6)=2(x-5)+3

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Solution for 7x-3(x-6)=2(x-5)+3 equation: 



7x-3(x-6)=2(x-5)+3

We move all terms to the left:

7x-3(x-6)-(2(x-5)+3)=0

We multiply parentheses

7x-3x-(2(x-5)+3)+18=0



We calculate terms in parentheses: -(2(x-5)+3), so:

2(x-5)+3

We multiply parentheses

2x-10+3

We add all the numbers together, and all the variables

2x-7

Back to the equation:

-(2x-7)



We add all the numbers together, and all the variables

4x-(2x-7)+18=0

We get rid of parentheses

4x-2x+7+18=0

We add all the numbers together, and all the variables

2x+25=0

We move all terms containing x to the left, all other terms to the right

2x=-25

x=-25/2

x=-12+1/2

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