7x-32=2/3(30x+18)-17x

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Solution for 7x-32=2/3(30x+18)-17x equation: 



7x-32=2/3(30x+18)-17x

We move all terms to the left:

7x-32-(2/3(30x+18)-17x)=0



Domain of the equation: 3(30x+18)-17x)!=0

x∈R



We multiply all the terms by the denominator


7x*3(30x+18)-17x)-(2-32*3(30x+18)-17x)=0

Wy multiply elements

21x^2(3-17x)-(2-96x(3-17x)=0



We calculate terms in parentheses: -(2-96x(3-17x), so:

2-96x(3-17x

determiningTheFunctionDomain
-96x(3-17x+2

Back to the equation:

-(-96x(3-17x+2)



We add all the numbers together, and all the variables

21x^2(-17x+3)-(-96x(-17x+5)=0



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-96x(-17x+5





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-96x(-17x+5





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-96x(-17x+5





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-96x(-17x+5





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