7x-3=2(2x-3)+3(x+1)

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Solution for 7x-3=2(2x-3)+3(x+1) equation: 



7x-3=2(2x-3)+3(x+1)

We move all terms to the left:

7x-3-(2(2x-3)+3(x+1))=0



We calculate terms in parentheses: -(2(2x-3)+3(x+1)), so:

2(2x-3)+3(x+1)

We multiply parentheses

4x+3x-6+3

We add all the numbers together, and all the variables

7x-3

Back to the equation:

-(7x-3)



We get rid of parentheses

7x-7x+3-3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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