7x-3x+7=3(x+2)+20

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Solution for 7x-3x+7=3(x+2)+20 equation: 



7x-3x+7=3(x+2)+20

We move all terms to the left:

7x-3x+7-(3(x+2)+20)=0

We add all the numbers together, and all the variables

4x-(3(x+2)+20)+7=0



We calculate terms in parentheses: -(3(x+2)+20), so:

3(x+2)+20

We multiply parentheses

3x+6+20

We add all the numbers together, and all the variables

3x+26

Back to the equation:

-(3x+26)



We get rid of parentheses

4x-3x-26+7=0

We add all the numbers together, and all the variables

x-19=0

We move all terms containing x to the left, all other terms to the right

x=19

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