7x-3x+7=3(x-4)+4

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Solution for 7x-3x+7=3(x-4)+4 equation: 



7x-3x+7=3(x-4)+4

We move all terms to the left:

7x-3x+7-(3(x-4)+4)=0

We add all the numbers together, and all the variables

4x-(3(x-4)+4)+7=0



We calculate terms in parentheses: -(3(x-4)+4), so:

3(x-4)+4

We multiply parentheses

3x-12+4

We add all the numbers together, and all the variables

3x-8

Back to the equation:

-(3x-8)



We get rid of parentheses

4x-3x+8+7=0

We add all the numbers together, and all the variables

x+15=0

We move all terms containing x to the left, all other terms to the right

x=-15

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