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7x-3x^2=4-6x
We move all terms to the left:
7x-3x^2-(4-6x)=0
We add all the numbers together, and all the variables
-3x^2+7x-(-6x+4)=0
We get rid of parentheses
-3x^2+7x+6x-4=0
We add all the numbers together, and all the variables
-3x^2+13x-4=0
a = -3; b = 13; c = -4;
Δ = b2-4ac
Δ = 132-4·(-3)·(-4)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-11}{2*-3}=\frac{-24}{-6} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+11}{2*-3}=\frac{-2}{-6} =1/3 $
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