7x-3x=-6x(x+10)+5(-3-3x)

Solution for 7x-3x=-6x(x+10)+5(-3-3x) equation:

7x-3x=-6x(x+10)+5(-3-3x)

We move all terms to the left:

7x-3x-(-6x(x+10)+5(-3-3x))=0

We add all the numbers together, and all the variables

7x-3x-(-6x(x+10)+5(-3x-3))=0

We add all the numbers together, and all the variables

4x-(-6x(x+10)+5(-3x-3))=0


We calculate terms in parentheses: -(-6x(x+10)+5(-3x-3)), so:

-6x(x+10)+5(-3x-3)

We multiply parentheses

-6x^2-60x-15x-15

We add all the numbers together, and all the variables

-6x^2-75x-15

Back to the equation:

-(-6x^2-75x-15)


We get rid of parentheses

6x^2+75x+4x+15=0

We add all the numbers together, and all the variables

6x^2+79x+15=0

a = 6; b = 79; c = +15;
Δ = b2-4ac
Δ = 792-4·6·15
Δ = 5881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(79)-\sqrt{5881}}{2*6}=\frac{-79-\sqrt{5881}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(79)+\sqrt{5881}}{2*6}=\frac{-79+\sqrt{5881}}{12}
$