7x-4(4x-19)=148

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Solution for 7x-4(4x-19)=148 equation: 



7x-4(4x-19)=148

We move all terms to the left:

7x-4(4x-19)-(148)=0

We multiply parentheses

7x-16x+76-148=0

We add all the numbers together, and all the variables

-9x-72=0

We move all terms containing x to the left, all other terms to the right

-9x=72

x=72/-9

x=-8

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