7x-4(x-2)=3x+8

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Solution for 7x-4(x-2)=3x+8 equation: 



7x-4(x-2)=3x+8

We move all terms to the left:

7x-4(x-2)-(3x+8)=0

We multiply parentheses

7x-4x-(3x+8)+8=0

We get rid of parentheses

7x-4x-3x-8+8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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