7x-4+3x+12=108

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Solution for 7x-4+3x+12=108 equation: 



7x-4+3x+12=108

We move all terms to the left:

7x-4+3x+12-(108)=0

We add all the numbers together, and all the variables

10x-100=0

We move all terms containing x to the left, all other terms to the right

10x=100

x=100/10

x=10

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