7x-4+3x+20=2(x-8)

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Solution for 7x-4+3x+20=2(x-8) equation:



7x-4+3x+20=2(x-8)
We move all terms to the left:
7x-4+3x+20-(2(x-8))=0
We add all the numbers together, and all the variables
10x-(2(x-8))+16=0
We calculate terms in parentheses: -(2(x-8)), so:
2(x-8)
We multiply parentheses
2x-16
Back to the equation:
-(2x-16)
We get rid of parentheses
10x-2x+16+16=0
We add all the numbers together, and all the variables
8x+32=0
We move all terms containing x to the left, all other terms to the right
8x=-32
x=-32/8
x=-4

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