7x-4+3x+20=2(x-8)

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Solution for 7x-4+3x+20=2(x-8) equation: 



7x-4+3x+20=2(x-8)

We move all terms to the left:

7x-4+3x+20-(2(x-8))=0

We add all the numbers together, and all the variables

10x-(2(x-8))+16=0



We calculate terms in parentheses: -(2(x-8)), so:

2(x-8)

We multiply parentheses

2x-16

Back to the equation:

-(2x-16)



We get rid of parentheses

10x-2x+16+16=0

We add all the numbers together, and all the variables

8x+32=0

We move all terms containing x to the left, all other terms to the right

8x=-32

x=-32/8

x=-4

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