7x-4x(x+1)=8

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Solution for 7x-4x(x+1)=8 equation:



7x-4x(x+1)=8
We move all terms to the left:
7x-4x(x+1)-(8)=0
We multiply parentheses
-4x^2+7x-4x-8=0
We add all the numbers together, and all the variables
-4x^2+3x-8=0
a = -4; b = 3; c = -8;
Δ = b2-4ac
Δ = 32-4·(-4)·(-8)
Δ = -119
Delta is less than zero, so there is no solution for the equation

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