7x-4x+7=3(x-4)+20

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Solution for 7x-4x+7=3(x-4)+20 equation:



7x-4x+7=3(x-4)+20
We move all terms to the left:
7x-4x+7-(3(x-4)+20)=0
We add all the numbers together, and all the variables
3x-(3(x-4)+20)+7=0
We calculate terms in parentheses: -(3(x-4)+20), so:
3(x-4)+20
We multiply parentheses
3x-12+20
We add all the numbers together, and all the variables
3x+8
Back to the equation:
-(3x+8)
We get rid of parentheses
3x-3x-8+7=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation

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