7x-5(9-3x)=3(x+12)-8x

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Solution for 7x-5(9-3x)=3(x+12)-8x equation:



7x-5(9-3x)=3(x+12)-8x
We move all terms to the left:
7x-5(9-3x)-(3(x+12)-8x)=0
We add all the numbers together, and all the variables
7x-5(-3x+9)-(3(x+12)-8x)=0
We multiply parentheses
7x+15x-(3(x+12)-8x)-45=0
We calculate terms in parentheses: -(3(x+12)-8x), so:
3(x+12)-8x
We add all the numbers together, and all the variables
-8x+3(x+12)
We multiply parentheses
-8x+3x+36
We add all the numbers together, and all the variables
-5x+36
Back to the equation:
-(-5x+36)
We add all the numbers together, and all the variables
22x-(-5x+36)-45=0
We get rid of parentheses
22x+5x-36-45=0
We add all the numbers together, and all the variables
27x-81=0
We move all terms containing x to the left, all other terms to the right
27x=81
x=81/27
x=3

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