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7x-5/2x-5=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
7x*2x-5*2x-5=0
Wy multiply elements
14x^2-10x-5=0
a = 14; b = -10; c = -5;
Δ = b2-4ac
Δ = -102-4·14·(-5)
Δ = 380
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{380}=\sqrt{4*95}=\sqrt{4}*\sqrt{95}=2\sqrt{95}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{95}}{2*14}=\frac{10-2\sqrt{95}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{95}}{2*14}=\frac{10+2\sqrt{95}}{28} $
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