7x-5/6x=3

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Solution for 7x-5/6x=3 equation:



7x-5/6x=3
We move all terms to the left:
7x-5/6x-(3)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
We multiply all the terms by the denominator
7x*6x-3*6x-5=0
Wy multiply elements
42x^2-18x-5=0
a = 42; b = -18; c = -5;
Δ = b2-4ac
Δ = -182-4·42·(-5)
Δ = 1164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1164}=\sqrt{4*291}=\sqrt{4}*\sqrt{291}=2\sqrt{291}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{291}}{2*42}=\frac{18-2\sqrt{291}}{84} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{291}}{2*42}=\frac{18+2\sqrt{291}}{84} $

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