7x-5=2(x+35)

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Solution for 7x-5=2(x+35) equation: 



7x-5=2(x+35)

We move all terms to the left:

7x-5-(2(x+35))=0



We calculate terms in parentheses: -(2(x+35)), so:

2(x+35)

We multiply parentheses

2x+70

Back to the equation:

-(2x+70)



We get rid of parentheses

7x-2x-70-5=0

We add all the numbers together, and all the variables

5x-75=0

We move all terms containing x to the left, all other terms to the right

5x=75

x=75/5

x=15

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