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7x-5=3(2x-1)-4x+1
We move all terms to the left:
7x-5-(3(2x-1)-4x+1)=0
We calculate terms in parentheses: -(3(2x-1)-4x+1), so:We get rid of parentheses
3(2x-1)-4x+1
We add all the numbers together, and all the variables
-4x+3(2x-1)+1
We multiply parentheses
-4x+6x-3+1
We add all the numbers together, and all the variables
2x-2
Back to the equation:
-(2x-2)
7x-2x+2-5=0
We add all the numbers together, and all the variables
5x-3=0
We move all terms containing x to the left, all other terms to the right
5x=3
x=3/5
x=3/5
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