7x-6(1-x)=8(x-2)

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Solution for 7x-6(1-x)=8(x-2) equation: 



7x-6(1-x)=8(x-2)

We move all terms to the left:

7x-6(1-x)-(8(x-2))=0

We add all the numbers together, and all the variables

7x-6(-1x+1)-(8(x-2))=0

We multiply parentheses

7x+6x-(8(x-2))-6=0



We calculate terms in parentheses: -(8(x-2)), so:

8(x-2)

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)



We add all the numbers together, and all the variables

13x-(8x-16)-6=0

We get rid of parentheses

13x-8x+16-6=0

We add all the numbers together, and all the variables

5x+10=0

We move all terms containing x to the left, all other terms to the right

5x=-10

x=-10/5

x=-2

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