7x-6/6x+7=x-2/x+1

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Solution for 7x-6/6x+7=x-2/x+1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7*x-((6/6)*x)+7 = x-(2/x)+1 // - x-(2/x)+1

7*x-((6/6)*x)-x+2/x-1+7 = 0

7*x-x-x+2/x-1+7 = 0

5*x^1+2*x^-1+6*x^0 = 0

(5*x^2+6*x^1+2*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^2+6*x^1+2*x^0) = 0

x^1

5*x^2+6*x+2 = 0

5*x^2+6*x+2 = 0

DELTA = 6^2-(2*4*5)

DELTA = -4

DELTA < 0

x in { } 

x belongs to the empty set

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