7x-9(2x+3)+38=4(3x+8)+25

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Solution for 7x-9(2x+3)+38=4(3x+8)+25 equation: 



7x-9(2x+3)+38=4(3x+8)+25

We move all terms to the left:

7x-9(2x+3)+38-(4(3x+8)+25)=0

We multiply parentheses

7x-18x-(4(3x+8)+25)-27+38=0



We calculate terms in parentheses: -(4(3x+8)+25), so:

4(3x+8)+25

We multiply parentheses

12x+32+25

We add all the numbers together, and all the variables

12x+57

Back to the equation:

-(12x+57)



We add all the numbers together, and all the variables

-11x-(12x+57)+11=0

We get rid of parentheses

-11x-12x-57+11=0

We add all the numbers together, and all the variables

-23x-46=0

We move all terms containing x to the left, all other terms to the right

-23x=46

x=46/-23

x=-2

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