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7x-9x^2=5x-6x=
We move all terms to the left:
7x-9x^2-(5x-6x)=0
We add all the numbers together, and all the variables
-9x^2+7x-(-1x)=0
We get rid of parentheses
-9x^2+7x+1x=0
We add all the numbers together, and all the variables
-9x^2+8x=0
a = -9; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-9)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-9}=\frac{-16}{-18} =8/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-9}=\frac{0}{-18} =0 $
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