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7x/5(2-9)=5x+8
We move all terms to the left:
7x/5(2-9)-(5x+8)=0
We add all the numbers together, and all the variables
7x/5(-7)-(5x+8)=0
We get rid of parentheses
7x/5(-7)-5x-8=0
We multiply all the terms by the denominator
7x-5x*5(-7)-8*5(-7)=0
We add all the numbers together, and all the variables
7x-5x*5(-7)+280=0
Wy multiply elements
-25x^2(-+280+7x=0
We use the square of the difference formula
-25x^2(-280+7x=0
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